Question

A Keystone Pipeline has a diameter of 36 inches and a design flow rate of 590,000 barrels per day of crude oil at 40ºC. Estimate the pump horsepower required if the length of the pipe is 1.9 mile(s). The pipe material is new steel. For crude oil at 40ºC, take μ ≈ 0.0053 kg/m-s ÷ 47.88 = 0.0000111 slug/ft-s. The density, with SG = 0.86, is 0.86(1.94) = 1.67 slug/ft3. Round the answer to the nearest whole number. Take f ≈ 0.0155.

Answer 1

Answer:

Power = 606.83 hp/mile

Explanation:

Given data:

diameter of pipeline is 36 inches = 3ft

flow rate is 590,000 barrels per day = 28.755 ft^3/sec

temperature of pipe = 46 degree celcius

length of pipe is 1.9 mile = 10032 ft

velocity of flow$= \frac{28.755}{\frac{\pi}{4} 3^2} = 4.068 ft/s$

applying bernouli eq at two point in pipeline

P1 = P2

v1 = v2

z1 = z2 so we have

$h_{in} = h_f$

$h_{in} = \frac{ flv^2}{2gD}$

$h_{in} = \frac{0.0155 \times 10032 \times 4.068^2}{2\times 32.174 \times 3}$

$h_{in} = 13.32 ft$

POwer $P = \rho gQ h_{in}$

   $P = 53.71 \times 32.174 \times 27.755 \times 13.32 = 634141.29 ldf ft/sec$

Power P = 1152.99 hp                   0

power needed for each mile $= \frac{1152.99}{1.9} = 606.83 hp/mile$