All categories

4 years ago

A 9.12 microFarad capacitor is measured to have a reactance of 268.0 Ohm. At what frequency (in Hz) is it being driven?

Physics

1 answer:

Katen [24]4 years ago

3 0

Answer:

65.14 Hz

Explanation:

We have given the capacitance $C=9.12\mu F=9.12\times 106{-6}F$

And the capacitive reluctance = 268 ohm

The capacitive reluctance of a capacitive circuit is given by

$X_C=\frac{1}{\omega C}$

$X_C=\frac{1}{2\pi f C}$

$268=\frac{1}{2\pi f \times 9.12\times 10^{-6}}$

$f=\frac{1}{2\times 3.14\times 268\times 9.12\times 10^{-6}}=65.14Hz$

You might be interested in

The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor?

Slav-nsk [51]

The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 * $10^{-6}$ C

Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.

Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.

charge = capacitance * voltage

Q = CV

= 3 * $10^{-6}$ * 15 v

= 45 * $10^{-6}$ C

To learn more about capacitance here

brainly.com/question/14746225

#SPJ4

8 0

2 years ago

A mass spectrometer was used in the discovery of the electron. In the velocity selector, the electric and magnetic fields are se

Mama L [17]

Answer:

Explanation:

Radius of dee, r = 8 mm = 0.008 m

Electric field, e = 400 V/m

Magnetic field, B = 4.7 x 10^-4 T

mass of electron, m = 9.1 x 10^-31 kg

charge of electron, q = 1.6 x 10^-19 C

(a) Let v is the speed of electrons.

$v = \frac{Bqr}{m}$

$v = \frac{4.7\times 10^{-4}\times 1.6\times 10^{-19}\times 0.008}{9.1 \times 10^{-31}}$

v = 661098.9 = 661099 m/s

(b)

$\frac{e}{m}=\frac{1.6 \times 10^{-19}}{9.1\times 10^{-31}}$

e / m = 1.76 x 10^14 C / kg

K = 0.5 x mv²

K = 0.5 x 9.1 x 10^-31 x 661099 x 661099

K = 1.99 x 10^-19 J

K = 1.24 eV

So, the potential difference is

V = 1.24 V

(d) if the acceleration voltage is doubled

V = 2 x 1.24 = 2.48 V

So, Kinetic energy

K = 2.48 eV

K = 2.48 x 1.6 x 10^-19 = 3.968 x 10^-19 J

Let v is the speed

K = 0.5 x mv²

3.968 x 10^-19 = 0.5 x 9.1 x 10^-31 x v²

v = 933856.5 m/s

Let the new radius is r.

$r=\frac{mv}{Bq}$

$r=\frac{9.1\times 10^{-31}\times 933856.5}{4.7\times 10^{-4}\times 1.6\times 10^{-19}}$

r = 0.0113 m = 1.13 cm

7 0

3 years ago

Two nuclei join to form a larger nucleus during which process

pentagon [3]

nuclear fusion- produces huge amounts of energy.

4 0

3 years ago

Read 2 more answers

The spectra of most stars are dark-line spectra because ________.

pav-90 [236]

Because dark line spectra result from passing white light through ionized gasses and plasmas, which is what the atmosphere of stars are made of. These frequencies are scattered by the star's atmosphere as it leaves the surface (photosphere) of the star, and don't make it to earth.

5 0

3 years ago

A wave has a wavelength of 9 mm and a frequency of 6 hertz. What is its speed?

Marrrta [24]

Speed = (frequency)x(wavelength).

Frequency = 6 Hz
Wavelength = 9mm = 0.009m.

Speed = (6 Hz) x (0.009m) = 0.054 m/s or 54 mm/sec.

5 0

3 years ago