Question

A 9.12 microFarad capacitor is measured to have a reactance of 268.0 Ohm. At what frequency (in Hz) is it being driven?

Answer 1

Answer:

65.14 Hz

Explanation:

We have given the capacitance $C=9.12\mu F=9.12\times 106{-6}F$

And the capacitive reluctance = 268 ohm

The capacitive reluctance of a capacitive circuit is given by

$X_C=\frac{1}{\omega C}$

$X_C=\frac{1}{2\pi f C}$

$268=\frac{1}{2\pi f \times 9.12\times 10^{-6}}$

$f=\frac{1}{2\times 3.14\times 268\times 9.12\times 10^{-6}}=65.14Hz$