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3 years ago

State What is the correct order of tasks for washing dishes in a three-compartment sink?

Physics

1 answer:

Nataliya [291]3 years ago

7 0

Answer:

The summary of the given statement is explained below throughout the explanation segment.

Explanation:

Drain certain surfaces throughout warm water of such soap during the very first sink. This same sanitizing of bacteria would not destroy whether grime would be in the direction.
Exfoliate the plates throughout plain water during the secondary drain. As with grime, the residual soap could avoid the kill off bacteria and viruses by the sanitizer.

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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.

aliina [53]

Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

$W=K_f - K_i$

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

$K_f$ is the final kinetic energy

$K_i = 66,120 J$ is the initial kinetic energy

Solving,

$K_f = K_i + W = 66,120 + (-36,733)=29,387 J$

Now we can find the final speed of the car by using the formula for kinetic energy

$K_f = \frac{1}{2}mv^2$

where

m = 661 kg is the mass of the car

v is its final speed

Solving for v, we find

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s$

3 0

3 years ago

A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at

baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

$\Sigma \tau = 0$

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)

- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
$\tau = r \times F$

Doing the summation using their respective lever arms:

$0 = L Tsin\theta - dF_g$

$dF_g = LTsin\theta$

Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

$tan\theta = \frac{H}{L}\\\\tan^{-1}(\frac{H}{L}) = \theta\\\\tan^{-1}(\frac{1.70}{2.200}) = 37.69^o$

Now, let's solve for 'T'.

$T = \frac{dMg}{Lsin\theta}$

Plugging in the values:
$T = \frac{(0.700)(4.00)(9.8)}{(2.200)sin(37.69)} = \boxed{20.399 N}$

3 0

1 year ago

A rock is dropped from the top of a building. after 4 seconds it is moving at 40 m/s. what was the acceleration of the rock

Marta_Voda [28]

Its moving 10 m/s every sec.

6 0

3 years ago

wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate

liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates $6.00\times 10^{-3} m^2$

distance between the plates is $1.50\times 10^{-4} m$

charge = $5.40\times 10^{-8} c$

we know that capacitance is given as

$C = \frac{\epsilon A}{d}$

$C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}$

$C = 3.54\times 10^{-10} F$

potential difference is given as

$V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}$

V = 152.542 volts

3 0

3 years ago

A rolling ball with a mass of 1.01 kg crashes into a wall. The wall exerts a force of 2.40 Newtons and stops the ball. What was

klemol [59]

Answer:

Acceleration, a = 2.38m/s²

Explanation:

Given the following data;

Mass = 1.01 kg

Force = 2.4N

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration, a = \frac{F}{m}$

Substituting into the equation, we have;

$Acceleration, a = \frac{2.4}{1.01}$

<em>Acceleration, a = 2.38m/s²</em>

<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>

3 0

2 years ago