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soldier1979 [14.2K]
3 years ago
12

The perimeter of a room is 43 ft. The width is 9 1 2ft. What is the length?

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

<em>answer = 12 \: ft \\ solution \\ perimeter = 43 ft\\ breadth = 9 \times \frac{1}{2} =  \frac{19}{2 }    = 9.5 \: ft\\  now \\ perimeter \: of \: \: rectangle = 2(l + b) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: or \:  43= 2(l + 9.5) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: or \: 43 = 2l + 19 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: or \:  - 2l = 19 - 43 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: or \:  - 2l =  - 24 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: or \: l =  \frac{ - 24}{ - 2}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: l = 12 \: ft \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

Anettt [7]3 years ago
3 0

Answer:

length = 12ft

Step-by-step explanation:

Given that,

width =9  \frac{1}{2}  = 9.5

Let's find the length

perimeter \\43  = 2(l + w) \\  43= 2(l + 9.5) \\ 43 = 2l + 19 \\ 43 - 19 = 2l \\ 24 = 2l \\  \frac{24}{2}  =  \frac{2l}{2}  \\ l = 12

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em> </em><em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em><em> </em>

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a) (14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

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Step-by-step explanation:

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p_v represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

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t_{\alpha/2}= 2.39

And replacing we got for the confidence interval:

(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis:\mu_{A} = \mu_{B}

Alternative hypothesis:\mu_{A} \neq \mu_{B}

the statistic is given by:

t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

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Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10  

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