Question

The magnitude of the electrostatic force between two identical ions that are separated by a distance of 8.3 × 10-10m is 192.9 × 10-9N.(a)What is the charge of each ion?(b)How many electrons are ""missing"" from each ion (thus giving the ion its charge imbalance)?

Answer 1

Answer:

(a) 1.215 x 10^-13 J

(b) n = 7.6 x 10^5

Explanation:

distance, r = 8.3 x 10^-10 m

Force, F = 192.9 x 10^-9 N

Let the charge is q.

(a) According to the Coulomb's law

$F=\frac{Kq\times q}{r^{2}}$

$192.9\times10^{-9}=\frac{9\times10^{9}\times q\times q}{\left (8.3\times 10^{-10} \right )^{2}}$

q = 1.215 x 10^-13 C

(b) Let n number of electrons are missing.

$n = \frac{q}{e}=\frac{1.215\times10^{-13}}{1.6\times10^{-19}}$

n = 7.6 x 10^5