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Elena L [17]
3 years ago
5

A tank is full of oil weighing 40 lb/ft^3. The tank is an inverted right circular cone (with the base at the top) with a height

of 5 feet and a radius of 2 feet. Find the work required to pump the water to a height of 1 feet above the top of the tank
Physics
1 answer:
krok68 [10]3 years ago
8 0

Answer:

26945.6 ft⋅lbf

Explanation:

Volume of Right Circular Cone = pi*(radius^2)*(height/3)

Pi*(4)*(5/3) = 20.94 ft^3

Density = Mass / Volume

Mass = Density*Volume

Mass = (40)*(20.94)

Mass = 837.6 lb

Work = Force*Height

Force = Mass*Acceleration

Acceleration will be gravitational acceleration

Work = (837.6)*(32.17)*(1)

Work = 26945.6 ft⋅lbf

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 <span>This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

Ff = UsN 

where Us is the coefficient of static friction and N is the normal force. 

In order to get the crate moving you must first apply enough force to overcome the static friction: 

Fapplied = Ff 

Since Fapplied = 43 Newtons: 

Fapplied = Ff = 43 = UsN 

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43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2</span>
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3 years ago
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the type of tomato plants used.

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3 years ago
A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

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Mass of mixture = 11.2 + 1.2 = 12.4kg

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I think it's the first one

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Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temp
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Answer:

2*10^9electrons

Explanation:

Remember that the net force will be zero at terminal voltege so

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3 years ago
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