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FrozenT [24]
4 years ago
15

For f(x)=√(2x+1) , find the following:

Mathematics
1 answer:
Wittaler [7]4 years ago
6 0

Part a.

The domain is the set of x values such that x \ge -\frac{1}{2}, basically x can be equal to -1/2 or it can be larger than -1/2. To get this answer, you solve 2x+1 \ge 0 for x (subtract 1 from both sides; then divide both sides by 2). I set 2x+1 larger or equal to 0 because we want to avoid the stuff under the square root to be negative.

If you want the domain in interval notation, then it would be \Big[ -\frac{1}{2} , \infty \Big) which means the interval starts at -1/2 (including -1/2) and then it stops at infinity. So technically it never stops and goes on forever to the right.

-----------------------

Part b.

I'm going to use "sqrt" as shorthand for "square root"

f(x) = sqrt(2x+1)

f(10) = sqrt(2*10+1) ... every x replaced by 10

f(10) = sqrt(20+1)

f(10) = sqrt(21)

f(10) = 4.58257569 which is approximate

-----------------------

Part c.

f(x) = sqrt(2x+1)

f(x) = sqrt(2(x)+1)

f(x+2a) = sqrt(2(x+2a)+1) ... every x replaced by (x+2a)

f(x+2a) = sqrt(2x+4a+1) .... distribute

we can't simplify any further

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there are 30 marked seals. In a survey, you count 58 seals, 16 of which were marked. About how many seals are in the area? Round
Rina8888 [55]

Answer:

109 seals

Step-by-step explanation:

Let

x -----> approximate total seals in the area

we know that

In a survey, you count 58 seals, 16 of which were marked

Using proportion

Find out how many seals are in the area , if there are 30 marked seals

\frac{58}{16} =\frac{x}{30}\\\\x=58(30)/16\\\\x=108.75\ seals

Round to the nearest whole number

108.75\ seals=109\ seals

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3 years ago
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Zinaida [17]
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kati45 [8]

Can’t do 16 but here are the rest :))

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4 years ago
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aivan3 [116]
Y= 58x + 55
They charge 58$ per hour therefore 58 should correlate with x and since when don’t know y (the total amount) its y= and then just add 55
7 0
4 years ago
Having Problems With This Question
hjlf

Answer:

f+g(2)=10

f-g(4)=-4

F/G(2)= 7/3

(f)(g)(1)=0

Step-by-step explanation:

1. (f+g)=2x+3+x^2-1 2(2)+2=10

2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4

3. f/g= 2x+3/x^2-1 4+3/3= 7/3

4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0

8 0
3 years ago
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