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WITCHER [35]
2 years ago
11

To identify a satirical tone, look for words an author uses to exaggerate a particular character behavior to make that person ap

pear ridiculous to the reader. A. True. B. False
Physics
1 answer:
Gre4nikov [31]2 years ago
5 0

To identify a satirical tone, look for words an author uses to exaggerate a particular character behavior to make that person appear ridiculous to the reader. The statement is True.

<h3>What is character?</h3>

What a person thinks upon a situation and get through it makes the character of a person and defines his behavior.

Given is a statement "To identify a satirical tone, look for words an author uses to exaggerate a particular character behavior to make that person appear ridiculous to the reader".

The words used by the person forms the character. So, the author searches for the word which says about his character but the reader finds it ridiculous.

Thus, the statement is true.

Learn more about character.

brainly.com/question/3756907

#SPJ1

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Marina86 [1]

Answer:

1. A Haploid

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5 0
4 years ago
Light incident on a Surface at an angle of 45° undergoes diffused reflection. At what angle will it reflect?
zhuklara [117]
The angle(s) that it will reflect will be at any angle between -90° and 90. The correct answer between all the choices given is the fourth choice or letter D. Lmk if this is correct
3 0
3 years ago
Read 2 more answers
A particular solid is an excellent conductor of thermal energy. Is it more likely to be a metal or a non-metal?
tensa zangetsu [6.8K]
It is more likely to be a metal. This is because metals are good heat conductors whereas non metals tend to be poor heat conductors.
8 0
3 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
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