-- An A300 Airbus commercial jet airliner, loaded with passengers, cargo,
and flight crew, cruising in a straight line, at 35,000 ft altitude, at a constant
speed of 530 miles per hour.
True because when the independent answer changes, then the dependent variable, which relies on the independent variable, changes.
Answer:
a. for any force, there is an equal and opposite reaction force.
Explanation:
Newton third law of motion states that " for every action, there is an equal and opposite reaction.
Action force= reaction force =
M₁ * a₁ = M₂ * a₂
where M₁ = mass of object 1
a₁ = acceleration due to object 1
M₂ = mass of object 2
a₂ = corresponding acceleration due to object 2
this happen in everyday life of an individual. an example is seen in a groups of three man exerting a push force on a static car, the push force on the car make the car to exhibit some motion equivalent to the force applied by the three man.
The change in momentum of the ball is 0.6Kgm/s.
To find the answer, we need to know about the momentum.
<h3>What's the expression of change in momentum during collision?</h3>
- The change in momentum= final momentum - initial momentum of the objects
- And momentum= mass × velocity
<h3>What's the change in momentum here?</h3>
- Here the initial momentum= 0.10×30=3Kgm/s
- Final momentum= 0.10×24= 2.4Kgm/s
- Change in momentum= 3-2.4= 0.6Kgm/s
Thus, we can conclude that the change in momentum is 0.6Kgm/s.
Learn more about the momentum here:
brainly.com/question/4126751
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Answer:
<h2>1/7 kg</h2>
Explanation:
Find the diagram attached for better understanding of the question.
Given the mass of one of the blocks to be 1.0kg and accelerates downward at 3/4g.
g = acceleration due to gravity.
Let the block accelerating downward be M, mass of the other body be 'm' and the acceleration of the body M be 'a'.
M = 1.0 kg and a = 3.4g
According to newton's second law;
For body of mass m;
T - mg = ma ... (1)
For body of mass M;
Mg - T = Ma ... (2)
Adding equation 1 ad 2;
+Mg -mg = ma + Ma
Ma-Mg = -mg-ma
M(a-g) = -m(a+g)
Substituting M = 1.0 kg and a = 3/4g into the resulting equation;
3/4 g-g = -m(3/4 g+g)
3/4 g-g = -m(7/4 g)
-g/4 = -m(7/4 g)
1/4 = 7m/4
28m = 4
m = 1/7 kg
Therefore the mass of the other box is 1/7 kg