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Inessa [10]
3 years ago
6

A 5-kg object slides down a frictionless surface inclined at an angle of 30º from the horizontal. The total distance moved by th

e object along the plane is 10 meters. The work done on the object by the normal force of the surface is?
Physics
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

Workdone =0

Explanation:

The body is inclined at θ=30°,     s=10m,  m=5kg

Workdone by the object = FsCosθ

but the surface is a friction-less surface, this means coefficient of friction =0

F=μR

F=0*R

F=0

W=FScosθ

W=0*SCosθ

W=0

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Answer:

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Explanation:

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         w_f = w₀ - a t

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