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Inessa [10]
4 years ago
6

A 5-kg object slides down a frictionless surface inclined at an angle of 30º from the horizontal. The total distance moved by th

e object along the plane is 10 meters. The work done on the object by the normal force of the surface is?
Physics
1 answer:
erma4kov [3.2K]4 years ago
7 0

Answer:

Workdone =0

Explanation:

The body is inclined at θ=30°,     s=10m,  m=5kg

Workdone by the object = FsCosθ

but the surface is a friction-less surface, this means coefficient of friction =0

F=μR

F=0*R

F=0

W=FScosθ

W=0*SCosθ

W=0

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The displacement of Itzel according to the question is 6.3 miles SW

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From the diagram, we can also se that the direction of the displacement in the South West direction.

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A 0.20 kg mass (m1) hangs vertically from a spring and an elongation of the spring of 9.50 cm (r1) is recorded. With a mass (m2)
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Answer:

k=320N/m

Explanation:

Step one:

given data

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Step two:

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