A 5-kg object slides down a frictionless surface inclined at an angle of 30º from the horizontal. The total distance moved by th e object along the plane is 10 meters. The work done on the object by the normal force of the surface is?
1 answer:
Answer:
Workdone =0
Explanation:
The body is inclined at θ=30°, s=10m, m=5kg
Workdone by the object = FsCosθ
but the surface is a friction-less surface, this means coefficient of friction =0
F=μR
F=0*R
F=0
W=FScosθ
W=0*SCosθ
W=0
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