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3 years ago

Somebody help please....

Mathematics

1 answer:

Tems11 [23]3 years ago

5 0

Answer:

4,096

Step-by-step explanation:

It goes like this 4 * -4=-16, 16*4=64, -64*4=256, etc.

You use the sum of the last number but flip the sin to make it opposite like if your some was + make it a negative to get your next product. Hope that made sense!!!!

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What's 2x+3(4x-3)=8-3x show your work pls

irga5000 [103]

Answer:

x=1

Step-by-step explanation:

Its x=1 because if we put the 1 as in x then it will be like 2(1)+3(4(1)-3)= 8-3(1)

2(1)+3(4(1)-3) is equal to 5

8-3(1) is equal to 5

5=5

so x is 1

3 0

3 years ago

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Solve in logarithms no scam 94100×√38.2\5.68^3×8.14 pls help don't scam pls

maks197457 [2]

Answer:

389.89879489

Step-by-step explanation:

1. Multiply

(5.68^3 × 8.14= 1491.65851648)

94100 × √38.2 / 1491.65851648

2. evaluate root

(√38.2 = 6.18061485)

94100 × 6.18061485 / 1491.65851648

3. multiply 

(94100 × 6.18061485 = 581595.85796324)

581595.85796324 / 1491.65851648

4. divide

(581595.85796324 / 1491.65851648 = 389.89879489)

8 0

3 years ago

Find the indicated side of the right triangle

Olenka [21]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 3\sqrt3$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: \tan(60) = \cfrac{x}{3}$

$\qquad \tt \rightarrow \: \sqrt{3} = \dfrac{x}{3}$

$\qquad \tt \rightarrow \: x = 3 \sqrt{3}$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago

Find the 22nd term of the arithmetic sequence whose common difference is d=4 and whose first term is a, = 3

gayaneshka [121]

Answer:

Step-by-step explanation:

t22 = a + (n- 1)d

t22 = 3 + 21*4

t22 = 3 + 84

t22 = 87

3 0

3 years ago

Evaluate: 2^-2 x (13x3)-5^3

Lapatulllka [165]

2^-2 x (13x3)-5^3

1/ (2^2) * 39 - 125

1/4 *39 -125

39/4 -125

9 3/4 - 125

factor out -1

- (125-9 3/4)

borrow to subtract the fraction

- (124 4/4 - 9 3/4)

- (115 1/4)

-115 1/4

6 0

4 years ago

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