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DedPeter [7]
3 years ago
11

12. Suppose you pay $3.00 to roll a fair die with the understanding that you will get back $5.00 for rolling a 1 or a 6, nothing

otherwise. What is your expected value?
$3.00
$-3.00
$5.00
$-1.33
Mathematics
1 answer:
Paul [167]3 years ago
3 0
<h2>In decimal value the answer is -1.33</h2>

<em>E = 5(2/6) + (-3)(4/6) = (10/6)-(12/6) = -2/6 = -1/3</em>

<em>E = -1/3 or about -0.33333.</em>

This is an unfriendly game because you are anticipated to lose 0.33 on every move in the long run.

<em>E = (1/6) ・ 0 + (1/6) ・ 0  +  (1/6) ・ 5 + (1/6) ・ 0 + (1/6) ・5 + (1/6) ・ 0 - 3</em>

<em>E = 5/3 - 3</em>

<em>E = -(4/3)</em>

Playing the game costs $3.

You win $5 if you roll 3 or 5, therefore you gain $2 ("+2").

If you roll a 1, 2, 4, or 6, you will not win anything and will lose $3. ("-3").

The predicted value is then calculated as

<em>(2/6) ・(2) + (4/6) ・(-3) = 2/3 - 2 = -(4/3)</em>

<h3>For every three games performed, you should expect to lose $4 in total.</h3>
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Answer:

4\frac{2}{3} guests.

Step-by-step explanation:

We have been given that there are 7/8 quarts of orange juice. Mrs. Mathewson would like to serve her guests 3/16 quarts orange juice.

To find the number of guests Mrs. Mathewson can serve with 7/8 quarts of juice, we will divide 7/8 by 3/16 as:

\text{Number of guests Mrs. Mathewson can serve}=\frac{7}{8}\div\frac{3}{16}

Convert to multiplication problem by flipping the 2nd fraction:

\text{Number of guests Mrs. Mathewson can serve}=\frac{7}{8}\times\frac{16}{3}

\text{Number of guests Mrs. Mathewson can serve}=\frac{7}{1}\times\frac{2}{3}

\text{Number of guests Mrs. Mathewson can serve}=\frac{14}{3}

\text{Number of guests Mrs. Mathewson can serve}=4\frac{2}{3}

Therefore, Mrs. Mathewson can serve orange juice to 4\frac{2}{3} guests.

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3 years ago
If a,b,c,d are in continuous proportion then prove that (c+a) (c+d) = (b+c) (b+d)​
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Answer:

We must prove that (c+a)(c+d) = (b+c)(b+d)

  1. Let us use principles from mathematical induction
  2. \frac{a}{b}  =  \frac{b}{c}  =  \frac{c}{d}  = x
  3. a=bx , b=cx, c=dx
  4. a+c = b + c
  5. c +d = b + d
  6. Such that (a+c)(c+d)=(b+c)(b+d)

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A video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to
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3 years ago
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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

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3. At the start of summer, Ben has $250 . He takes a summer
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Answer:

Week 4

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Ben has $250 in the beginning.  He saves $150 per week.

y = 150x + 250

Tim has $1,650 in the beginning.  He spends $200 per week.

y = 1650 - 200x

We are trying to find which x-value produces the same y-value for both equations.  You can do this by setting both equations equal to each other.

150x + 250 = 1650 - 200x

(150x + 250) + 200x = (1650 - 200x) + 200x

350x + 250 = 1650

(350x + 250) - 250 = (1650) - 250

350x = 1400

(350x)/350 = (1400)/350

x = 4

By week 4, they will have the same amount of money.

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