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zaharov [31]
4 years ago
13

Any help with 2 and 9 would be greatly appreciated. I need it ASAP if possible.

Physics
1 answer:
taurus [48]4 years ago
4 0

Here is for #2.

Answer:

She has a Velocity of 4.0

Explanation:

Δv = ΔM /m

So in our case is is Δ4.000 = Δ220 /55

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An LC circuit consists of a 3.4-µF capacitor and a coil with a self-inductance 0.080 H and no appreciable resistance. At t = 0 t
alexira [117]

Answer

given,

capacitance = C = 3.4-µF

inductance = L = 0.08 H

frequency is expressed as

f = \dfrac{1}{2\pi\sqrt{LC}}

time period

T = \dfrac{1}{f}=2\pi\sqrt{LC}

after time T/4 current reach maximum

 t = \dfrac{T}{4}

 t = \dfrac{2\pi\sqrt{LC}}{4}

 t = \dfrac{2\pi\sqrt{0.08 \times 3.4 \times 10^{-6}}}{4}

        t = 8.2 x 10⁻⁴ s

        t = 0.82 ms

b) using law of conservation

  \dfrac{1}{2}CV^2=\dfrac{1}{2}LI^2

  I^2 = \dfrac{CV^2}{L}

  I^2 = \dfrac{C}{L}\dfrac{Q^2}{C^2}

  I =\sqrt{\dfrac{Q^2}{CL}}

  I =\sqrt{\dfrac{(5.4 \times 10^{-6})^2}{0.08 \times 3.4 \times 10^{-6}}}

       I = 0.010 A

       I = 10 mA

4 0
4 years ago
In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

- a horizontal motion, with constant velocity

- a vertical motion, with constant acceleration g=9.8 m/s^2 towards the ground

In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

v(t)=v_0 -gt

And it decreases until the ball reaches its maximum height, then it starts increasing again.

4 0
4 years ago
is this true or false? an object with a mass of 9.0kg has an acceleration of 3m/s2. the force acting on it is 3N
ludmilkaskok [199]

The answer is "False". The force acting on the object is 27 N.

According to Newton's second law, when a force <em>F</em> acts on am object of mass <em>m</em>, it produces an acceleration <em>a</em>. The force is given by the expression,

F=ma

Thus, if the body has a mass of 9.0 kg and if it has an acceleration of 3 m/s², then, on substituting the values in the equation for force,

F=ma\\ =(9.0kg)(3m/s^2)\\ =27N

Thus, it can be seen that the force acting on the body is 27 N and not 3 N as is mentioned in the statement. Hence the statement is false.

5 0
3 years ago
What is the relationship between the normal force and weight
GalinKa [24]

Answer: they have the same magnitude.

Explanation:

normal force = mg

weight = mg

4 0
3 years ago
HELP PLEEAAAASSSEEEEEEE What is the definition of net force?
aleksley [76]

Answer:

the sum of all force being applied to an object.

Explanation:

8 0
3 years ago
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