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Naddik [55]
3 years ago
7

A little bumblebee accelerates uniformly at 1.5 m/s² from rest to 22 m/s. Immediately upon reaching 22m/s, the brakes are applie

d, and it stops 2.5 s later. Find the total distance traveled.
Physics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

190 m

Explanation:

Displacement during acceleration:

v² = v₀² + 2a(x - x₀)

(22 m/s)² = (0 m/s)² + 2(1.5 m/s²)(x - 0 m)

x = 161.333 m

Displacement after deceleration:

x = x₀ + ½ (v + v₀)t

x = 161.333 m + ½ (0 m/s + 22 m/s)(2.5 s)

x = 188.833

Rounded to 2 sig-figs, the bumblebee travels a distance of 190 m.

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A 1 000-V battery, a 3 000-Ω resistor, and a 0.50-μF capacitor are connected in series with a switch. The time constant for such
vampirchik [111]

Answer:

The current in the circuit at a time interval of τ seconds after the switch has been closed is 0.123 A

Explanation:

The time constant for an R and C in series circuit is given by τ = RC.

R = 3000 ohms, C = 0.5 × 10⁻⁶ F = 5.0 × 10⁻⁷ F

τ = 3000 × 5 × 10⁻⁷ = 0.015 s

The voltage across a capacitor as it charges is given be

V(t) = Vs (1 - e⁻ᵏᵗ)

where k = 1/τ

At the point when t = τ, the expassion becomes

V(t = τ) = 1000 (1 - e⁻¹) = 0.632 × 1000 = 632 V

Current flows as a result of potential difference,.

Current in the circuit at this time t =  τ is given by

I = (Vs - Vc)/R

Vs = source voltage = 1000 V

Vc = Voltage across the capacitor = 632 V

R = 3000 ohms

I = (1000 - 632)/3000 = 0.123 A

6 0
4 years ago
How do its eight arms help an octopus obtain food
Andrews [41]
The more arms it has the less of a chance the prey has to swim away.
5 0
3 years ago
The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car travelling
Crank
270/70^2  = x/80^2

Cross multiply

270 (6400) = 4900x   

x = 270(6400)/4900

352 and 32/49 feet

Hope this helps


4 0
3 years ago
Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Earth he is moving at 60 m/s
Andrej [43]

Answer:

  Potential energy = 73.575 kJ

  Kinetic energy = 135kJ

  Total mechanical energy = 208.575 kJ

Explanation:

   The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

  The kinetic energy of a body is given by KE=\frac{1}{2} mv^2, where v is the velocity and m is the mass of body.

  Total mechanical energy = Kinetic energy + Potential energy

  KE=\frac{1}{2} mv^2=\frac{1}{2} *75*60^2= 135000J = 135kJ

  PE = mgh = 75*9.81*100 = 73575 J = 73.575 kJ

  Total mechanical energy = Kinetic energy + Potential energy = 135+73.575

                                             = 208.575 kJ    

4 0
3 years ago
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the
azamat

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

<h3>What is force?</h3>

Force is defined as the product of mass and acceleration of an object.

Friction is defined as the force that resists the movement of an object over another.

Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

Learn more about force here:

brainly.com/question/12970081

#SPJ12

7 0
2 years ago
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