An object attached to an ideal massless spring is pulled across a frictionless surface. If the spring constant is 45 N/m and the
spring is stretched by 0.88 m when the object is accelerating at what is the mass of the object?
1 answer:
Answer:
Incomplete questions
We are not given the acceleration of the motion , check attachment for complete question
Explanation:
Given that
Spring constant (k)=45N/m
The extension (e)=0.88m
Also given that the acceleration is 2m/s²
Force by the spring is given as
Using hooke's law
F=ke
F=45×0.88
F=39.6N
Now this force will set the object in motion, now using newton second law of motion
F=ma
Then, m=F/a
m=39.6/2
m=19.8kg
The mass of the object is 19.8kg which is approximately 20kg
The correct option is C
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