Which statement defines reduction potential when considering a pair of half-cell reactions?

1 answer:

3 0

Reduction is the gain of electrons, then potential of reducción is the tendency of a sustance to gain electrons. In this case the sustance is an electrode.

Then the reduction potential refers to the tendency of one electrode to gain electrons and it is measured against a standard electrode which is the electrode of hydorgen.

When you consider the pair of half-cell reactions, the potential of the cell is the reduction potential - oxidation potential.

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Which of the following represents the atomic number of an element?

Anna11 [10]

Answer:

The atomic number is the number of protons in the nucleus

4 0

3 years ago

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jasenka [17]

Answer:

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Explanation:

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3 years ago

You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0

3 years ago

The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would the vapor pressure be 0.500 atm? (∆Hvap = 28.5

NNADVOKAT [17]

For a normal boiling point of a liquid is 282 °C, the temperature is mathematically given as

T2=181.55°C\

<h3> What temperature (in °C) would the vapor pressure be 0.500 atm? </h3>

Generally, the equation for the gas is mathematically given as

ln(p1/p2)=dHvap/R(1/T2-1/T1)

Therefore

ln(1/0.26)=23500/8.214(1/T2-1/555)

T2=181.55^C

In conclusion

T2=181.55°C