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borishaifa [10]
3 years ago
11

Susie cooked sausages on a barbecue. Fat and water in the sausages changed state. which two changes of state occur during this p

rocess? a. Fat melted b. Water evaporated
Chemistry
1 answer:
padilas [110]3 years ago
5 0

Answer:

The options a and b are correct

Explanation:

This options provided to the question are the answers to the question. But for clarification. When the fat melts, the change of state that occurs here is from solid to liquid (which is called melting) while the change of state that occurs when the water evaporated is from liquid to gas (which is called evaporation).

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Please Help! Let P and V represent the pressure and volume of Xe(g). If a piston is used to reduce the volume of the gas to V/2
Elza [17]

1) 2P

2) Average speed does not change

Explanation:

1)

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

pV=const.

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

p_1 V_1 = p_2 V_2

where:

p_1 = P is the initial pressure

V_1=V is the initial volume

V_2=\frac{V}{2} is the final volume

Solving for p2, we find the final pressure:

p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P

So, the pressure has doubled.

2)

The average speed of the atoms/molecules in the gas is given by the formula

v_{rms}=\sqrt{\frac{3RT}{M}}

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

v_{rms} is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

8 0
3 years ago
Potassium chlorate is a white, crystalline solid. It can be broken down into potassium chloride (a salt)
lions [1.4K]

Answer:

Notice that the number of atoms of

K

and

Cl

are the same on both sides, but the numbers of

O

atoms are not. There are 3

O

atoms on the the left side and 2 on the right. 3 and 2 are factors of 6, so add coefficients so that there are 6

O

atoms on both sides.

2KClO

3

(

s

)

+ heat

→

KCl(s)

+

3O

2

(

g

)

Now the

K

and

Cl

atoms are not balanced. There are 2 of each on the left and 1 of each on the right. Add a coefficient of 2 in front of

KCl

.

2KClO

3

(

s

)

+ heat

→

2KCl(s)

+

3O

2

(

g

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The equation is now balanced with 2

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7 0
3 years ago
Read 2 more answers
Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of
Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles

Now we have to calculate the moles of PbO

The balanced chemical reaction is,

2Pb(s)+O_2(g)\rightarrow 2PbO(s)

From the reaction, we conclude that

As, 2 mole of Pb react to give 2 mole of PbO

So, 2.18 mole of Pb react to give 2.18 mole of PbO

Now we have to calculate the mass of PbO

\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO

\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g

Theoretical yield of PbO = 486.1 g

Experimental yield of PbO = 367.5 g

Now we have to calculate the percent yield of the reaction.

\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100

\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%

Therefore, the percent yield of the reaction is, 75.6 %

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