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juin [17]
3 years ago
6

Please help answer this

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
5 0
Thats how u answer the question

Yakvenalex [24]3 years ago
3 0

1. a) 4(2/5)= (5*4+2)/5=22/5 b) 6(3/4)=(4*6+3)/4=27/4 c) 3(2/11)=(11*3+2)/11=35/11

2.a) 32/7=4(4/7) b) 53/4=13(1/4) c) 43/3=14(1/3)

3.a) 3/4+3/12=9/12+3/12=12/12=1 b) 3/5+3/20=12/20+3/20=15/20=3/4

c) 2/9+5/27=6/27+5/27=11/27

4. 1/2*43=43/2=21.5   >   3/4*28=21

Good luck!!!

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an athletic sock manufacturer make two different lengths of socks calf length or ankle length. You can buy the socks in navy blu
ryzh [129]
Calf - blue, white, elastic, fat top, no elastic                                                            ankle - blue, white, elastic, fat top, no elastic 


5 0
3 years ago
2⋅10^ 4 −7 ^3 =? First person to solve gets 10 Points and will also be rewarding branliest answer (Btw already know this answer
8_murik_8 [283]

Answer:

19657

Step-by-step explanation:

2\cdot 10^4 - 7^3=20000-343=19657

Hope this helps!

5 0
3 years ago
Please help me with this one question! Any help is welcomed, thanks in advance!
Mekhanik [1.2K]
Point slope form is  y - y1 = m(x - x1)

so if the slope is m= 2 and (x1,y1) = (1,3) is a point on the line the equation is:-

  y - 3 = 2(x - 1)
7 0
3 years ago
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
What is the slope of the line that contains these points?<br><br>Slope:
Semenov [28]

Answer:

-4

Step-by-step explanation:

Slope formula:

m=y2-y1/x2-x1

I will use (-1,10) and (1,2)

2-10/1-(-1)

Which is

-8/2

Divide:

-4

Thus the slope is -4

Hope this helps!

5 0
2 years ago
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