Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Answer:
that would be 4253.28 feet
that would be 1296.4 m
Step-by-step explanation:
I think that's the answer and I hope it helps :)
Valid because 3 x 3 is 9 :))
Answer:
10
Step-by-step explanation:
Means back the numbers into multiples of several small numbers
Like:; 1. We take LCM of 40
Just break into multiples of small number
40= 2×2×2×5
2. We take LCM of 50
50= 5×5×2
So LCM for 100 is 2×2×5×5
after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)
Then write the the single number in place of two multipled numbers
Like:; 2×2 is written as 2 // 3×3 is written as 3
So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)
write pairs in single number 2×5
And so we get 2×5=10
So we find root of 100 that is 10