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If the force of gravity suddenly stopped acting on the planets, they would

lorasvet [3.4K]

Answer:c

Explanation:

If the Force of gravity suddenly stops acting on Planets then Planets would continue to move straight in the initial direction.

Gravity constantly acts on Planets to change their trajectory each instant thus in absence of it if a planet is moving in a circular path then it would follow the path of the tangent to the circular path as gravity force is absent to change its trajectory.

4 0

3 years ago

Calculate the work done by a 47N force pushing a pencil 0.26m

erastovalidia [21]

According to my examination I have confirmed that I do NOT repeat do NOT know this.

4 0

3 years ago

Where should be the best fit line be drawn on a scatterplot?

eimsori [14]

A line of best fit is a straight line drawn through the most points on a scatter plot, with an equal number of points above and below the line. It is used to investigate the nature of the relationship between two variables. The correct option is d.

A straight line with the best fit is one that minimizes the distance between it and some data.

In a scatter plot of varying data points, the line of best fit is used to express a relationship. It is a result of regression analysis and can be used to forecast indicators and price movements.

It is important to note that your line does not need to pass through any of the points on the plot; it only needs to bisect the area that contains the data points.

Thus, none of the options are correct, the correct one is d.

For more details regarding line of best fit, visit:

brainly.com/question/14279419

#SPJ1

8 0

1 year ago

A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west

Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

$\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}$

(see the attached graphic)

We have

ducks (relative to wind) = 7.0 m/s in some direction θ relative to the positive horizontal direction, or

$\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)$

wind (relative to Earth) = 5.0 m/s due East, or

$\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)$

ducks (relative to earth) = some speed v due South, or

$\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)$

Then by setting components equal, we have

$\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0$

$\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v$

We only care about the direction for this question, which we get from the first equation:

$\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}$

$\cos\theta=-\dfrac57$

$\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)$

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies both equations. We want

$\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v$

which means θ must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0

3 years ago

A truck drives with a constant linear speed v_iv i v, start subscript, i, end subscript down a road with two curves. The first

Alex

Answer:

(C) Decreases by factor of 3

Explanation:

Centripetal acceleration is given by

$a = \dfrac{v^2}{r}$

where v is the linear velocity and r is the radius of the curve.

Let the centripetal acceleration on the curve of radius R be $a_1$ .

Then

$a_1 = \dfrac{v_i^2}{R}$

Let the centripetal acceleration on the curve of radius 3R be $a_2$ .

Then

$a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1$

Here, we see that the acceleration decreases by a factor of 3.

7 0

3 years ago