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3 years ago

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Explain how sociology will contribute to the understanding of daily life and what is happening within it?

1 answer:

Helen [10]3 years ago

8 0

Answer:

Explain how sociology will contribute to the understanding of daily life and what is happening within it?

Sociology is the study of society of human being, how they develop and those things put in place for such development

Explanation:

Sociology helps to develop culture, how people interact with one another and this boost the relationship and development as far as human society is concerned.

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What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)

inna [77]

The force of gravity on the object is 14.47 N

Explanation:

The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by

$F=mg$

where

m is the mass of the object

g is the acceleration of gravity at the location of the object

IN this problem, we have:

m = 24.52 kg (mass of the object)

$g=0.59 m/s^2$ (acceleration of gravity on Pluto)

Substituting, we find the force of gravity on the object:

$F=(24.52)(0.59)=14.47 N$

Learn more about forces and weight:

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#LearnwithBrainly

7 0

3 years ago

Hello<br>what is zenith define it ?

sertanlavr [38]

Answer:

hi,

When one stands at a particular place, the point in the sky directly above the head is called Zenith.

Explanation:

hope it helps(≡^∇^≡)

good day

thank u ✅

4 0

2 years ago

A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera

AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel $r=0.3\ m$

Initial angular velocity $\omega _0=0$

It rotates 3 revolution in 5 s therefore

$\omega =2\pi 3=\6\pi =18.85\ rad/s$

using $\omega =\omega _0+\alpha t$

where $\alpha =angular\ acceleration$

$\omega =Final\ angular\ velocity$

$t=time$

$\alpha =\frac{18.85}{5}=3.77 rad/s^2$

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

$\omega at t=1$

$\omega =0+3.77\times 1=3.77 rad/s$

$a_c=\omega ^2\cdot r$

$a_c=(3.77)^2\cdot 0.3=4.26 m/s^2$

Tangential acceleration $a_t=\alpha \times r$

$a_t=3.77\times 0.3=1.13 m/s^2$

$a_{net}=\sqrt{a_t^2+a_c^2}$

$a_{net}=\sqrt{(1.13)^2+(4.26)^2}$

$a_{net}=4.41 m/s^2$

7 0

3 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

Flura [38]

Answer:

The mass of the wheel is 2159.045 kg

Explanation:

Given:

Radius $r = 0.330$

m

Force $F = 290$ N

Angular acceleration $\alpha = 0.814 \frac{rad}{s^{2} }$

From the formula of torque,

Γ $= I\alpha$ (1)

Γ $= rF$ (2)

$rF = I \alpha$

Find momentum of inertia $I$ from above equation,

$I = \frac{rF}{\alpha }$

$I = \frac{0.330 \times 290}{0.814}$

$I = 117.56$ $Kg. m^{2}$

Find the momentum inertia of disk,

$I = \frac{1}{2} Mr^{2}$

$M = \frac{2I}{r^{2} }$

$M = \frac{2 \times 117.56}{(0.330)^{2} }$

$M = 2159.045$ Kg

Therefore, the mass of the wheel is 2159.045 kg

8 0

3 years ago

What is the formula for force?

Vitek1552 [10]

Choice 'b' is one possible way to state
Newton's second law of motion.

The other choices are meaningless.

8 0

3 years ago