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4 years ago

7

What are the letters that stand for the elements

2 answers:

dalvyx [7]4 years ago

8 0

They are the element symbols. Too many to list here, look up a periodic table.

tester [92]4 years ago

8 0

i am supplying you with the table

hope this helps

^-^

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3 years ago

A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What

spin [16.1K]

Answer:

The wavelength is $\lambda_ 1 = 574.2 nm$

Explanation:

From the question we are told that

The thickness is $t = 198 nm = 198 *10^{-9 }\ m$

The refractive index of the non-reflective coating is $n_m = 1.45$

The refractive index of glass is $n_g = 1.50$

Generally the condition for destructive interference is mathematically represented as

$2 * n_m * t * cos (\theta) = n * \lambda$

Where $\thata$ $\theta$ is the angle of refraction which is 0° when the light is strongly transmitted

and n is the order maximum interference

so

$\lambda = \frac{2 * n * t * cos (\theta )}{n}$

at the point n = 1

$\lambda _1 = \frac{2 * 1.45 * 198*10^{-9} * cos (0 )}{1}$

$\lambda_1 = 574.2 *10^{-9}$

$\lambda_1 = 574.2 nm$

at n =2

$\lambda _2 = \frac{\lambda _1 }{2}$

$\lambda _2 = \frac{574.2*10^{-9} }{2}$

$\lambda _2 = 2.87 1 *10^{-9} \ m$

$\lambda _2 = 287. 1 nm$

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$390 \ nm \to 700 \ nm$

So the wavelength of visible light that is been transmitted is

$\lambda_ 1 = 574.2 nm$

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