Answer:
d = 69 .57 meter
Explanation:
First case
Speed of car ( v ) = 20.5 mi/h = 9.164 M/S
distance ( d ) = 11.6 meter ( m = mass of the car )
Work done = 0.5 m v² = 0.5 * 9.164² * m J = 41.99 m J
Force = ( workdone /distance ) = ( 41.99 m / 11.6 ) = 3.619 m N
Second case
v = 50.2 mi/h = 22.44135 m/s
d = ?
Work done = 0.5 * 22.44² * m J = 251.7768 * m J
Since the braking force remains the same .
3.619 m = ( 251.7768 m / d )
d = 69 .57 meter
It will possibly be A) chemical b/c it can make a sound like when the bar hits the ball it makes a sound correct?! and also it created heat especially when it hits the ball. and when the ball MOVES and the bar HITS it creates kinetic energy, but when you hit the ball it doesn’t create a new substance.
bonded pairs of electrons, lone pairs of electrons.
Answer:
m1/m2 = 0.51
Explanation:
First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:
V = √F/u
This is the equation that describes the relation between speed of a pulse and a force exerted on it.
the value of "u" is:
u = m/L
Where m is the mass of the rod, and L the length.
Now, for the rod 1:
V1 = √F/u1 (1)
rod 2:
V2 = √F/u2 (2)
Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:
1.4V2 = √F/u1 (3)
Replacing (2) in (3):
1.4(√F/u2) = √F/u1 (4)
Now, let's solve the equation 4:
[1.4(√F/u2)]² = F/u1
1.96(F/u2) =F/u1
1.96F = F*u2/u1
1.96 = u2/u1 (5)
Now, replacing the expression of u into (5) we have the following:
1.96 = m2/L / m1/L
1.96 = m2/m1 (6)
But we need m1/m2 so:
1.96m1 = m2
m1/m2 = 1/1.96
m1/m2 = 0.51
Answer:
0.375
Explanation:
When the 3rd sphere touches the 1st one, the charge will then be distributed between both of them, then now the 1st sphere has only half of his original charge.
In this moment then
Sphere 1 has a charge = Q/2
Sphere 3 has a charge = Q/2
When the 3rd sphere touches the 2nd sphere again the charge is distributed in a manner that both sphere has the same charge.
How the total charge is
Q = Q/2 + Q = 3/2Q,
When the spheres are separated each one has 3/4Q
Sphere 2 has a charge = 3/4Q
Sphere 3 has a charge = 3/4Q
The electrostatic force that acts on sphere 2 due to sphere 1 is:
F = (kq1q2) / r²
F = (Q/2 * 3Q/4) / r²
F = (Q² * 3) / 8r²
From the question, F = 0.42 = kQ²/r²
Thus, we can say that
F = (0.42 * 3) / 8
F = 0.1575
Thus, the ratio between F/F =
0.1575 / 0.42
Ratio, r = 0.375