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katovenus [111]
3 years ago
7

Suppose you know a golf ball's horizontal velocity and the time it has traveled through the air. how could you calculate how far

the ball traveled
Physics
1 answer:
Murrr4er [49]3 years ago
8 0

Given the time and the horizontal velocity, we can simply compute for the distance how far the ball travelled using the formula:

distance = velocity * time

 

<span>Since velocity is in units of m/s and time is seconds, therefore we can directly get a unit in meters.</span>

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A spring has a spring constant of 100 N/m, and the mass hanging from is is 0.71 kg. What is the period of the spring's motion?
Anuta_ua [19.1K]

k = spring constant of the spring = 100 N/m

m = mass hanging from the spring = 0.71 kg

T = Time period of the spring's motion = ?

Time period of the oscillations of the mass hanging is given as

T = (2π) √(m/k)

inserting the values in the above equation

T = (2 x 3.14) √(0.71 kg/100 N/m)

T = (6.28) √(0.0071 sec²)

T = (6.28) (0.084) sec

T = 0.53 sec

hence the correct choice is D) 0.53

6 0
3 years ago
Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?
enyata [817]
It is a seismograph that would be most useful.
6 0
3 years ago
Contrast the force of gravity between these pairs of objects a 1 kg mass and a 2 kg mass that are 1 m apart and two 2 kg masses
Yuki888 [10]

Solution

Force between pair of objects of masses 1kg and 2kg that are 1m apart is given as

F=G\times \frac{1\times 2}{1^2}

here G is gravitational constant

G=6.674\times10^{-11}Nm^2kg^{-2}

therefore,

F=6.674\times10^{-11}Nm^2kg^{-2}\times 2

F=13.348\times10^{-11}Nm^2kg^{-2}

similarly Force between pair of objects of masses 2kg each that are 1m apart is given as

F'=G\times \frac{2\times 2}{1^2}

F'=6.674\times10^{-11}Nm^2kg^{-2}\times 4

F'=2\times 13.348\times10^{-11}Nm^2kg^{-2}

or F'=2F

it means  Force between pair of objects of masses 2kg each that are 1m apart is equal to twice the Force between pair of objects of masses 1kg and 2kg that are 1m

7 0
3 years ago
A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of
umka21 [38]

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

(a)If line is moving up with constant velocity i.e. there is no acceleration

This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

Maximum weight in this case will be 50 N

(b)acceleration of magnitude 2.98 m/s^2

T-mg=ma

50=m\left ( g+a\right )

50=m\left ( 12.78\right )

m=3.91

Therefore weight is 3.91\times 9.8=38.34 N

7 0
4 years ago
To rid the body of wastes, including excess water and salts" is the purpose of what human body system? A) Digestive B) Excretory
Verizon [17]
Digestive I believe.


5 0
4 years ago
Read 2 more answers
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