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3 years ago

Round 14.613 to the nearest tenth

2 answers:

6 0

Given that the number in the hundredths place is a 1, and 1 is less than 5, everything in and past the hundredths place will be 0. And the tenths place will remain untouched.
The answer is 14.6.

Alona [7]3 years ago

5 0

$14.613\approx14.6$

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PLEASE HELP ME!!!!! what is the perimeter and area of this figure?

Pavel [41]

Answer:

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Step-by-step explanation:

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I can't find the surface area, is this confusing me.

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3 years ago

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Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe

Rama09 [41]

You can see how this works by thinking through what's going on.

In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97

What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

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3 years ago

What are the zeros of the function f(x)=x^2-2x-15?

valkas [14]

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Since this is a quadratic function, we must use the quadratic formula, which is:

$\frac{-b +/- \sqrt{b^{2} - 4(a)(c) } }{2a}$

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

$\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}$

which simplifies to:

$\frac{2 +/- \sqrt{(4 + 60} }{2}$

Simplified further:

$\frac{2 +/- \sqrt{(64} }{2}$
$\frac{2 +/- 8 }{2}$
And divide it by the 2 on the bottom gives us:

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So the zeros of this function are -2 and 6

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3 years ago

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Estimate the instantaneous rate of change of P(t) = 2t² + 3 at the point t = – 3

elena55 [62]

Step-by-step explanation:

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3 years ago