Answer:
see below
Step-by-step explanation:
A multiplier on the function value moves its y-coordinate farther from the x-axis by that multiplier value. It is the stretch factor. Stretch factors less than 1 cause the graph to be compressed vertically.
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A multiplier on the independent variable means it doesn't need to be as large to give the same function value. That is, multiplication of x by a factor of k compresses the graph horizontally by that factor of k. Equivalently, it does a horizontal stretch by a factor of 1/k.
Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so

In this problem we have

substitute



therefore
Polygon q’s area is one fourth of polygon p’s area
Answer:
13? This is a total guess, I haven't done perimeter in years.... I feel bad for you!
Step-by-step explanation:
Sorry if it's wrong
As the picture highlights, the opposite sides have the same lengths. The perimeter is the sum of all lengths, so we have

Plug the required value for the perimeter and expand the right hand side:

Simplify the right hand side:

Add 36 to both sides:

Divide both sides by 12:

Now that we know the value for s, let's deduce the lengths of the sides:

