Answer:
See explanation
Explanation:
In a chemical reaction, a particular reaction path may be favoured due to the fact that it is energetically more favourable(lower energy sigma complex is formed).
The more the resonance structures produced in a particular reaction pathway, the more energetically favourable it is.
In the chlorination of bromobenzene, ortho attack and para attack are preferred because each of these pathways involves a sigma complex with__4________resonance structures. Attack at the meta position involves formation of a sigma complex with only____3_______ resonance structures. The reaction will proceed more rapidly via the_____lower_______ energy sigma complex, so attack takes place at the ortho and para positions in preference to the meta position.
Lithium and Francium, they are both in the sane group therefore share similar characteristics
Air has a lower heat capacity which is the property of a material that describes how much heat energy is required to change the temperature of a substance by one degree Celsius <span />
Answer:
Here's what I get
Explanation:
The three resonance forms of N₂O are shown in the first diagram below (you can also use horizontal dashes to represent the bonding pairs).
To get the formal charge (FC) on the atoms, cut each bond in half, as in the second diagram.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) In Structure A
Left-hand N:
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 3 lone pairs(6) + 1 bonding electron = 7
FC = 5 - 6 = -1
(b) In Structure B
Left-hand N:
VE = 5
BE = 2 lone pairs (4)+ 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 6
FC = 6 - 6 = 0
(c) In Structure C
Left-hand N:
VE = 5
BE = 3 lone pairs (6)+ 1 bonding electrons = 6 + 1 = 7
FC = 5 - 7 = -2.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 1 lone pair(2) + 3 bonding electrons = 5
FC = 6 - 5 = +1