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Vladimir [108]
3 years ago
12

Explain the regiochemical outcome for chlorination of bromobenzene.

Chemistry
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

See explanation

Explanation:

In a chemical reaction, a particular reaction path may be favoured due to the fact that it is energetically more favourable(lower energy sigma complex is formed).

The more the resonance structures produced in a particular reaction pathway, the more energetically favourable it is.

In the chlorination of bromobenzene, ortho attack and para attack are preferred because each of these pathways involves a sigma complex with__4________resonance structures. Attack at the meta position involves formation of a sigma complex with only____3_______ resonance structures. The reaction will proceed more rapidly via the_____lower_______ energy sigma complex, so attack takes place at the ortho and para positions in preference to the meta position.

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Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 10-8 at 700°C. 2 H2S(g) 2 H2(g) + S2(g) If
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Answer:

The equilibrium concentration of hydrogen gas is 0.0010 M.

Explanation:

The equilibrium constant of the reaction = K_c=9.30\times 10^{-8}

Moles of hydrogen sulfide = 0.31 mol

Volume of the container = 4.1 L

[concentration]=\frac{moles}{volume (L)}

[H_2S]=\frac{0.31 mol}{4.1 L}=0.076 M

2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initially

0.076 M

At equilibrium

(0.076-2x)                         2x     x

The expression of an equilibrium constant :

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.076-x)^2}

Solving for x:

x = 0.00051

The equilibrium concentration of hydrogen gas:

[H_2]=2x=2\times 0.00051 M=0.0010 M

4 0
4 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

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Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

    NO2– + H2O -----> NO3– + 2H+

     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

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