Question

Determine the moles of chlorine needed to react with 38.9 of iron (III) chloride.

Answer 1

Answer: 0.360 moles

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} FeCl_3=\frac{38.9g}{162.2g/mol}=0.240moles$

The balanced chemical reaction is:

$2Fe+3Cl_2\rightarrow 2FeCl_3$  

According to stoichiometry :

2 moles of require = 3 moles of

Thus 0.240 moles of $FeCl_3$ will require=$\frac{3}{2}\times 0.240=0.360moles$ of $Cl_2$

Thus 0.360 moles of chlorine needed to react to produce 38.9 of iron (III) chloride.