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3 years ago

Determine the moles of chlorine needed to react with 38.9 of iron (III) chloride.

Chemistry

1 answer:

lys-0071 [83]3 years ago

6 0

Answer: 0.360 moles

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} FeCl_3=\frac{38.9g}{162.2g/mol}=0.240moles$

The balanced chemical reaction is:

$2Fe+3Cl_2\rightarrow 2FeCl_3$

According to stoichiometry :

2 moles of require = 3 moles of

Thus 0.240 moles of $FeCl_3$ will require= $\frac{3}{2}\times 0.240=0.360moles$ of $Cl_2$

Thus 0.360 moles of chlorine needed to react to produce 38.9 of iron (III) chloride.

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3 years ago

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Dafna11 [192]

Answer:

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In C, true because the more the valence electrons, the more the stability of an atom.

In D, true as electron placing is important and the reactivity of an atom is important.

So C and D are true!

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