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Pavel [41]
3 years ago
11

Which of the following is TRUE? A) The equivalence point is where the amount of acid equals the amount of base during any acid-b

ase titration. B) At the equivalence point, the pH is always 7. C) An indicator is not pH sensitive. D) A titration curve is a plot of pH vs. the [base]/[acid] ratio. E) None of the above is true.
Chemistry
2 answers:
liberstina [14]3 years ago
5 0

Answer:

the correct option is B

Explanation:

The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .

Finger [1]3 years ago
5 0

Answer:

E) None of the above is true

Explanation:

A) is wrong. The unit for amount of substance is the mole. The moles of acid equal the moles of base only when the molar ratio is 1:1. If the molar ratio is different, you will use different moles of acid and base used to reach the equivalence point.

B) is wrong. The pH = 7 only for a strong acid-strong base titration. If you have a weak acid or base, the pH at the equivalence point will not be 7.

C) is wrong. An indicator is pH sensitive. It shows distinct colours in different pH ranges.

D) is wrong. A titration curve is a plot of pH vs. the volume of titrant.

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1. Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O
vovikov84 [41]
1) Balanced equation

C3H8 + 5O2 -> 3 CO2 + 4 H2O

2) 0.700 L C3H8

Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio

1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2

0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8

x = 3.500 L O2

3) CO2 produced

1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>

x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2

4) Water vapor produced

1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>

x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O
3 0
4 years ago
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WITCHER [35]

rdxtyctjhb hhgfdgfbgngu6vtyhgfngmb vcAnswer:

Explanation:

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Done

4 0
3 years ago
The initial volume of a gas at a pressure of 3 atm is 5.2 L. What will the volume be if the pressure is increased to 15 atm?
julsineya [31]

Answer:

1 L

Explanation:

Use Boyle's Law, which is defined as:

p1v1 = p2v2

p1 = 3atm

v1 = 5.2L

p2 = 15atm

v2 = ?

We are solving for v2 because all other variables are given.

p1v1 = p2v2

(3atm)(5.2L) = (15atm)(v2)

v2 = (3)(5.2) / (15) = 1.04 L ≈ 1 L

5 0
3 years ago
How many grams of O₂ can be prepared from the thermal decomposition of 4.27 kg of HgO? Name and calculate the mass (in kg) of th
babymother [125]

Mass of Oxygen is: 0.784gm

Potassium chlorate is KClO3 and the decomposition looks like this...

2KClO3 ==> 2KCl + 3O2

4.50 g KClO3 x 1 mole/122.55 g = 0.0367 moles

0.0367 moles KClO3 x 3 moles O2/2 moles KClO3 = 0.0245 moles O2 (see mole ratio in balanced equation)

mass of O2 = 0.0245 moles O2 x 32 g/mole = 0.784 g O2 formed

<h3>What is the pressure of a mixture of CO2 and KR?</h3>

A mixture of CO2 and Kr weighs 37.0 g and exerts a pressure of 0.737 atm in its container. is expensive, you wish to recover it from the mixture.

<h3>How much oxygen is created when one mole of potassium chlorate breaks down?</h3>

in the reaction 2K C lO3 2K C l + 3O2 K C lO3? This demonstrates that 3 moles of oxygen gas are created for every 2 moles of degraded potassium chlorate.

<h3>How is high pressure liquid CO2 produced?</h3>

High pressure liquid CO 2 is produced by compressing the gaseous CO 2 in multistage compressors to pressures in the neighbourhood of 69 bar (1000,76 psi) pressure, then cooling it to around 18 °C (64,4 °F). It is customarily filled into specially constructed steel cylinders.

Learn more about decomposition HgO:

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5 0
2 years ago
How do valence electrons relate to the chemical reactions of an element?
RoseWind [281]

Answer:

Explanation:

Valance electrons are loosely held electrons of an atom. They are involve in chemical reaction. Consider the example of metals such as group two metals. All these have two valance electrons. They needed six electrons to complete the octet or loses two valance electrons to get complete octet. Thus its easier to remove two electrons than getting six electrons. These metals remove two electrons and form cations.

Now consider the example of nonmetals such group sixteen. They needed two electrons to get complete octet or remove six electrons to get complete octet. Thus its easier for them to get two electrons and they form anion. When group two metals cation and group sixteen anions combine they form compound and chemical reaction occur.

Group two metals also combine with halogens. Two halogens atoms combine with one alkaline earth metal atom to cancel the charge and make compound neutral.

They react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

2Mg  +   O₂   →    2MgO

2Ca +   O₂   →    2CaO

Oxygen carry -2 charge while Ca, Mg and Ba +2 and make the compound neutral because charges are equal in magnitude.

With sulfur,

Mg + S   →  MgS

Ca + S   →  CaS

Ba + S   →  BaS

Sulfer carry -2 charge while Ca, Mg and Ba +2 and make the compound neutral because charges are equal in magnitude.

3 0
4 years ago
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