All categories

2 years ago

Volume of 8.29ml and a mass of 16.31g

Chemistry

1 answer:

strojnjashka [21]2 years ago

3 0

Density = mass/volume = 16.31/8.29 = 1.96 g/mL.

Hope this helps!

You might be interested in

A property of a particle that affects<br> how it behaves around other particles

ASHA 777 [7]

Answer:

An elementary particle can be one of two groups: a fermion or a boson. Fermions are the building blocks of matter and have mass, while bosons behave as force carriers for fermion interactions and some of them have no mass. The Standard Model is the most accepted way to explain how particles behave, and the forces that affect them. According to this model, the elementary particles are further grouped into quarks, leptons, and gauge bosons, with the Higgs boson having a special status as a non-gauge boson.

4 0

2 years ago

If you filter a mixture of sand and salt-water, what will the solid residue in the filter paper consist of?

julia-pushkina [17]

Sand only bc the salt dissolved and sand doesn't

8 0

2 years ago

I need help with writing the formula compounds by cross crossing them

ElenaW [278]

Use your head or a formula website.

5 0

3 years ago

When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac

slega [8]

<h2>Answer:</h2> $1.33*10^{-2}grams$

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

$\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}$

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

$\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}$

Determine the mass of water produced

$\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}$

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0

9 months ago

According to the work principle, the ration of work output to work input is always _____.

vekshin1

Answer:

less than one.

Explanation:

5 0

2 years ago