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2 years ago

A car increased its velocity to 62m/s in 10s starting from rest. Calculate the distance it covers during this time?

Physics

2 answers:

Roman55 [17]2 years ago

6 0

Answer:

distance= velocity ×time

distance= 62×10

distance=620m

hope it helps you mate please mark me as brainliast

rjkz [21]2 years ago

4 0

Answer:

d = 620 m

Explanation:

Hi there !

Velocity formula

v = d/t => d = v×t

d = 62m/s×10s

= 620 m

Good luck !

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Ksenya-84 [330]

Answer:

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Explanation:

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2 years ago

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2 years ago

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The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee

lara [203]

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Explanation:

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$|r|=\sqrt{27.3^2+43.6^2}$

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initial velocity=0m/s. The skydiver doesn’t start with any speed because she is on the plane or helicopter.

final velocity=16m/s This is the velocity (speed) the skydiver reaches

The equation we use is KE=.5mv^2
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KE=.5(55kg)(16m/s)^2
KE=.5(55kg)(256m/s)
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babymother [125]

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