Answer:
The location is at (3.535, 1.162) m
Solution:
As per the question:
Mass of the projectile, m = 9.6 kg
Initial velocity, v = 12.4 m/s
Angle, 
Mass of one fragment, m = 6.5 kg
Time taken by the fragment, t = 1.42 s
Height of the fragment, y = 5.9 m
Horizontal distance, x = 13.6 m
Now,
To determine the location of the second fragment:
Horizontal Range, 

Time of flight, t' = 
Now, for the fragments:
Mass of the other fragment, m' = M - m = 9.6 - 6.5 = 3.1 kg
Distance traveled horizontally:

Distance traveled vertically:


Now,


x' = 3.535 m
Similarly,


The location of the other fragment is at (3.535, 1.162)