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3 years ago

If you were to be drawn into a black hole, what would happen? To the black hole, not to you.

Physics

1 answer:

love history [14]3 years ago

7 0

Answer:

It grows

Explanation:

The blacks holes will absorb

Me hoizontally stretching me like a noodle by the spaghtification process,thus growing bigger.

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There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________

salantis [7]

Answer:

The bell has a potential energy of 8550 [J]

Explanation:

Since the belt is 45 [m] above ground level, only potential energy is available. And this energy can be calculated by means of the following equation.

$E_{p}= W*h\\E_{p} = 190*45\\E_{p}=8550[J]$

8 0

3 years ago

A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the

Paha777 [63]

Answer:

c. V = 2 m/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

so:

Mgh = $\frac{1}{2}IW^2 +\frac{1}{2}MV^2$

where M is the mass, g the gravity, h the altitude, I the moment of inertia of the pulley, W the angular velocity of the pulley and V the velocity of the mass.

Also we know that:

V = WR

Where R is the radius of the disk, so:

W = V/R

Also, the moment of inertia of the disk is equal to:

I = $\frac{1}{2}MR^2$

I = $\frac{1}{2}(5kg)(2m)^2$

I = 10 kg*m^2

so, we can write the initial equation as:

Mgh = $\frac{1}{2}IV^2/R^2 +\frac{1}{2}MV^2$

Replacing the data:

(5kg)(9.8)(0.3m) = $\frac{1}{2}(10)V^2/(2)^2 +\frac{1}{2}(5kg)V^2$

solving for V:

(5kg)(9.8)(0.3m) = $V^2(\frac{1}{2}(10)1/4 +\frac{1}{2}(5kg))$

V = 2 m/s

8 0

3 years ago

What are the output waveforms of the following waves, after passing through a transformer?

Ber [7]

The output waveforms after passing through the transformer actually depend on the type of transformer used. It could either be a step-up transformer (steps voltage up), or a step-down transformer (steps voltage down). Both transformers have an output voltage in a form of a sine wave.

8 0

3 years ago

A father is pulling his child on a sled in the snow. According to Newton’s Third Law, the force the father exerts on the sled is

viktelen [127]

That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.

5 0

3 years ago

A particle cannot generally be localized to distances much smaller than its de Broglie wavelength. This fact can be taken to mea

Vlada [557]

The De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°

<h3>How is the De broglie wavelength of a thermal neutron at room temperature calculated?</h3>

Temperature, T = 300K

Momentum, p = mv

Therefore v = p/m

Energy, E= 1/2 m( p/m) ²

Boltzman Energy= 3/2 KT

3/2KT = 1/2 m(p/m)²

Therefore p = $\sqrt{3RTm}$

According to De broglie hypothesis, P = h ÷ λ

Therefore, λ = h ÷ $\sqrt{3RTm}$

= 6.6× $10^{-34}$ ÷ $\sqrt{3 \times 1.38 \times 10^{-23} \times 300 \times 1.6 \times 10^{-27} }$

= 0.15 × $10^{-9}$

Therefore the De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°

To learn more about De broglie wavelength, refer: <u>https://brainly.in/question/6131028</u>

#SPJ4

6 0

2 years ago