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Lerok [7]
2 years ago
6

What do ethical guidelines for research with human subjects mean?

Physics
1 answer:
gladu [14]2 years ago
4 0

By minimizing harms and risks and maximize benefits , respect human dignity, privacy and autonomy, take special precautions with vulnerable population and strive to distribute the benefits and burdens of research fairly

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You have to run 2.2 miles in track. How far is that in feet? There are 5280 feet in 1 mile
Greeley [361]

Answer:

11616ft^{2} or 11616

Explanation:

Since there are 5280 feet in 1 mile

you do 2.2 × 5280

2.2 × 5280 = 11616

8 0
3 years ago
Technician A says that in a series circuit, if one light goes out, the rest of the lights stay on. Technician B says that in a p
vivado [14]

Answer:

Explanation:

Technician A is incorrect as in series circuit the current is the same for all the resistors and if one bulb fails in the path then the circuit is incomplete and therefore no flow of current.

Technician B is correct as in parallel circuit there are multiple paths for current through which it can pass and malfunctioning of one resistor does not affect the other.      

6 0
3 years ago
What is the momentum of a 20 kg object traveling at a rate of 5 m/s
Arlecino [84]
100 as momentum=mass×velocity
3 0
3 years ago
Which geologic feature would most likely be represented by contour lines drawn far apart from one another?
Anna [14]
It would most definitely not be a hill or a cliff. I believe it would be a plain.
5 0
3 years ago
Work of 5 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (i
densk [106]

Answer:

Explanation:

Given that,

5J work is done by stretching a spring

e = 19cm = 0.19m

Assuming the spring is ideal, then we can apply Hooke's law

F = kx

To calculate k, we can apply the Workdone by a spring formula

W=∫F.dx

Since F=kx

W = ∫kx dx from x = 0 to x = 0.19

W = ½kx² from x = 0 to x = 0.19

W = ½k (0.19²-0²)

5 = ½k(0.0361-0)

5×2 = 0.0361k

Then, k = 10/0.0361

k = 277.008 N/m

The spring constant is 277.008N/m

Then, applying Hooke's law to find the applied force

F = kx

F = 277.008 × 0.19

F = 52.63 N

The applied force is 52.63N

6 0
3 years ago
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