Answer:
1.63 s
Explanation:
The skier lands on the sloped section when the direction of its velocity is exactly identical to that of the slope, so at 
below the horizontal.
This occurs when the magnitude of the vertical velocity is equal to the horizontal velocity (in fact, 
, and since 
and so 
.
We already know the horizontal velocity of the skier:
And this is constant during the entire motion.
The vertical velocity instead is given by
where
is the initial vertical velocity (zero since the skier flies off horizontally)
g = 9.8 m/s^2
t is the time
Here we have chosen the downward direction as positive direction.
Substituting 
, we find the time:
Answer:
1.) 113500J
2.) 237m
Explanation:
Hello!
To solve this exercise follow the following steps, the description and complete process is in the attached image
1. Draw the full sketch of the problem.
2. The work is defined as the product of the trajectory by the force that is parallel to this direction, for this reason to find the work done we multiply the horizontal distance (250m) by the applied force (454N)
3. The potential energy is equal to the product of mass, gravity and height and is equal to the work done by the force applied by the cyclist, of this relationship and using algebra we can find the height that the cyclist climbed
4. We use the sine function to find the diagonal distance using the height and angle of the slope
<span>ultraviolet light for sure is the right answer </span>
Answer:
When an object vibrates, it causes movement in surrounding air molecules. These molecules bump into the molecules close to them, causing them to vibrate as well. This makes them bump into more nearby air molecules.
Answer:
The motion of a simple pendulum is very close to Simple Harmonic Motion (SHM). SHM results whenever a restoring force is proportional to the displacement, a relationship often known as Hooke's Law when applied to springs. Where F is the restoring force, k is the spring constant, and x is the displacement.
where θ is the angle the pendulum makes with the vertical. For small angles, sin(θ)∼θ, which would then lead to simple harmonic motion. For large angles, this approximation no longer holds, and the motion is not considered to be simple harmonic motion.
