Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
The zebra danios are longer because if they are 4/3 the lenth bigger they would be the longest.
#1 is 4,-2
#2 is I cnt figure out
#3 is 12,-8
Answer:
D
Step-by-step explanation:
IF you count the dots for each graph, you would see that the minimum for B is Higher than group A's maximum, Therefore, the numbers do not overlap. This means that at a simple glance you can see which company does better.
Total outcomes: 52- 1% chance of any card
Outcomes for each type of card(heart, diamond,spades,cloves): 4 -25%
hope this helps