One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=
![( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29)
=(3)(3)=9
the answer is 9
Answer:
its A, B, C or D
Step-by-step explanation:
it has to be one of them.
Answer: See below
Explanation:
6a + 11 = 2a + 83
6a - 2a = 83 - 11
4a = 72
a = 72/4
a = 18
Answer:
a) 3x5³
b) 75
Step-by-step explanation:
a) find the Prime factors of 375 by dividing your number by prime numbers (you answers must be whole) use a factor tree to help you
a) do the same to 150
one you have you answers in this case we have
375- 3x5x5x5
150 - 2x3x5x5
you collect all the like terms, this will be 3x5x5 then you just simply multiply it And it gives you 75