

keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference
Answer:y=
1
2
x4+
7
2
x3+
9
2
x2+
−27
2
x−27
Step-by-step explanation:
Answer:
Step-by-step explanation:

Use the order of operations.
Note: PEMDAS or BODMAS stands for:
<u>PEMDAS</u>
- <u>Parentheses</u>
- <u>Exponents</u>
- <u>Multiply</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>BODMAS</u>
- <u>Brackets</u>
- <u>Order</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>First, do parentheses.</u>
3+6*(5+4)÷3-7
(5+4)=9

<u>Do multiply and divide.</u>
6*9=54
54/3=18
<u>Then, rewrite the problem down.</u>

<u>Add.</u>



- <u>Therefore, the correct answer is "C. 14".</u>
I hope this helps, let me know if you have any questions.
These quantities are related linearly with slope
3/2. without knowing the answer choices I can only give you examples of equations that fit
y-2=3/2(x-2). or y=3/2(x) -1
etc
Answer: I think it is 5 or 4