If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
Answer:
C. 3
Step-by-step explanation:
You know the angle sum is ...
∠FGT +∠TGH = ∠FGH
You can use this relation with the given values to find x.
90 + (8x +4) = 39x +1
93 = 31x . . . . . . . . . . . . . add -1-8x, collect terms
3 = x . . . . . . . . . . . . . . . . divide by 31
Answer:
XQ = 12
Step-by-step explanation:
In this question it asks for XQ instead of x, but you need to find x first.
1. Find x.
XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)
Solve for x.
3x - 3 = 2(2x - 6)
Distribute 2.
3x - 3 = 4x - 12
Isolate x.
3x = 4x - 9
-x = -9
Divide -1 out.
x = 9
Now solve for XQ, which the equation is given.
XQ = 2(9) - 6
XQ = 18 - 6
XQ = 12
Answer:
relative minimum would be your awnser
