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3 years ago

Three things about the body systems?

Chemistry

1 answer:

makvit [3.9K]3 years ago

5 0

Answer:

Three things about our body's systems:

All systems have a method of self-regulation or exogenous regulation by other systems.

All systems have a balance in their functions.

All the systems of our organism are intertwined with each other thus giving general vitality.

Explanation:

Best known systems:

Renal, respiratory, circulatory, cardiac, nervous, immune, blood, muscular systems.

All of them include the participation of one or more organs

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Which phrase describes a valence electron?(1 point)

liraira [26]

Answer: I THINK C

Explanation: It has a 25% chance of being right so I'd wait if I were you just sayin

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2 years ago

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If faucet drips 5 mL of water each minute, what is the volume of water dripped at the end of five minutes?

kiruha [24]

If the faucet drops at 5 mL per minute you just have to do the following steps to find out.

5 mL for the dripping rate times 5 for the minutes.

The answer would result being 25mL

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3 years ago

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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

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3 years ago

Plzzz help me! I will do anything ;) How many molecules are there in 45g of caffeine

babymother [125]

Answer:

45 IS THE ANSWER

Explanation:

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3 years ago

3.0 x 108 m/s is the

Veseljchak [2.6K]

Answer:

Speed of light

Explanation:

The value 3.0 x 10⁸m/s is taken as the speed of light.

It is a constant.

It implies that light travels a distance of 3 x 10⁸ in just one second.
This value is for the speed of light in a vacuum when there are not particles obstructing its movement.
The speed of electromagnetic radiations in free space is also taken as the speed of light.

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3 years ago