<h3>
Answer:</h3>
126.14 g
<h3>
Explanation:</h3>
- Complete combustion of hydrocarbons yields water and carbon dioxide.
- Methane is a hydrocarbon in the homologous series known as alkanes.
- Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.
CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
<u>We are given;</u>
We are required to determine the mass of H₂O produced
<h3>Step 1: Moles of H₂O produced</h3>
- From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.
Therefore, Moles of methane = Moles of H₂O × 2
Hence, Moles of H₂O = 7.0 moles
<h3>Step 2: Mass of H₂O produced </h3>
We know that; mass = Moles × Molar mass
Molar mass of water = 18.02 g/mol
Therefore;
Mass of water = 7.0 moles × 18.02 g/mol
= 126.14 g
Thus, the mass of water produced is 126.14 g
-delta H symbolises an exothermic reaction. Hence, it gives off heat. Reversely, it would absorb heat.
Answer:
3.0002 moles
Explanation:
Data Given:
mass of NO₂ = 138.01 g
No. of moles NO₂ = ?
Solution
To find mass of sample mole formula will be used
mole formula
no. of mole = mass in grams / molar mass
Molar mass of NO₂ = 14 + 2(16)
Molar mass of NO₂ = 14 + 32 = 46 g/mol
Put values in above equation
no. of mole = 138.01 g / 46 g/mol
no. of mole = 3.0002 moles
no. of mole of NO₂ = 3.0002 moles
