<h2>Step 1 : Identify the given </h2>
Volume = 250mL
Density = 1.19 g/ML
<h2>Step 2 . Calculate the mass of HCL </h2>
Density = mass/volume
∴Mass = Density * Volume
= 1.19g/mL* 250mL
= 297,5g
<h2>Step 3 : Calculate the total mass of the solution, given that concentration HCL is 38% </h2>
Mass of the total solution can be calculated by the following :
38% = Mc /297.5 * 100
Mc = 38/100 *297.5
= 113.05grams
• Finally, this means that mass of the total solution of 0.125M HCL i,s 113grams, ,you would use this mass to prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0%
2.469 could be maid dont forget to hit that thanks button
Answer:
The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.
Explanation:
The given reaction equation is not balanced because:
- Number of hydrogen atoms on both sides are not equal that is 4 on reactants side and 2 on products side.
- Number of oxygen atoms on both sides are not equal that is 3 on reactants side and 2 on products side.
In a balanced chemical equation number of atoms of each elements are equal on both sides.
So, the balanced chemical equation will be:
<span>We look at the end of the day:
n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
