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Ahat [919]
2 years ago
9

What's different about the valence electrons of Carbon and Silicon?

Chemistry
1 answer:
STatiana [176]2 years ago
3 0

Carbon is smaller in size than Silicon. ... Carbon has high ionization enthalpy than silicon and lower electron gain enthalpy than Si! Explanation: It is placed in the periodic table before Silicon and lack a d-orbital smaller size due to which effective nuclear force on the valence shell is much higher than in Si!

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Balance the chemical equation below: CO2 + H2O + 2678 kJ-> C6H1206 + O2 a. How many moles of H20 are involved in this reactio
11Alexandr11 [23.1K]

Answer:

a) 6 mol H2O

b) this reaction is endothermic

c) when 1 mol of CO2 is used, in the reaction they occur 0.5025 KJ

Explanation:

balanced eq:

  • 6CO2 + 6H2O + 2678 KJ ↔ C6H12O6 + 6O2

                                         6 - C - 6

                                         18 - O - 18

                                          12 - H - 12

a) mol H2O = 6 mol.......from balanced equation.

b) ΔE = 2678 KJ....... this reaction absorbs heat ( ΔE is positive )

c)    1 gramo C6H12O6 ≅ 4 cal

  • Mw C6H12O6 = 180.156 g/mol

⇒ 1mol CO2 * ( mol C6H12O6 / 6mol CO2 ) =0.166 mol C6H12O6

⇒ 0.166mol C6H12O6 * ( 180.156 g C6H12O6 / mol ) = 30.026g C6H12O6

⇒30.026 gC6H12O6 * ( 4 cal / gC6H12O6 ) * ( Kcal / 1000 cal ) * (4184 J / Kcal ) * ( KJ / 1000 J ) = 0.5025 KJ C6H12O6.

8 0
3 years ago
How to balance lead and silver acetate yields lead (||) acetate and silver
arsen [322]
The given elements put into an equation using their symbols  are as follows:
Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2
3 0
3 years ago
What is the freezing point of a solution of 0.5 mol of LiBr in 500 mL of water? (Kf = 1.86°C/m) –1.86°C –7.44°C –5.58°C –3.72°C
tresset_1 [31]

Answer:

  • Last choice: <em><u>- 3.72°C</u></em>

Explanation:

The freezing point depression in a solvent is a colligative property: it depends on the number of solute particles.

The equation to predict the freezing point depression in a solvent is:

  • ΔTf = Kf × m × i

Where,

  • ΔTf is the freezing point depression of the solvent,
  • m is the molality,
  • Kf is the cryoscopic molal constant of the solvent, and i is the Van'f Hoff factor, which is the number of ions produced by each unit formula of the ionic compound.

The calcualtions are in the attached pdf file. Please, open it by clicking on the image of the file.

Download pdf
6 0
3 years ago
How many significant figures in 8400
IrinaK [193]

Answer:

there are two significant figures is the number 8400

Explanation:

5 0
3 years ago
Read 2 more answers
Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M
lukranit [14]
I think you want to ask about Keq. At equilibrium, we can know [SO2Cl2] is 2.2*10-2 M -1.3*10-2M=9*10^-3 M. And [SO2]=[Cl2]. So the Keq=1.88*10^-2.
5 0
3 years ago
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