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Novay_Z [31]
3 years ago
9

Write the scientific notation in numerals. 1.2 x 104

Chemistry
1 answer:
ivanzaharov [21]3 years ago
8 0
1.2*104 is 12000 it is easy just try ur best
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A chemist must prepare of 800.0 ml potassium hydroxide solution with a pH of 13.00 at 25°.
ArbitrLikvidat [17]

Answer:

4.48 grams is the mass of potassium hydroxide that the chemist must weigh out in the second step.

Explanation:

The pH of the solution = 13.00

pH + pOH = 14

pOH = 14 - pH = 14 - 13.00 = 1.00

pOH=-\log[OH^-]

1.00=-\log[OH^-]

[OH^-]=10^{-1.00} M=0.100 M

KOH(aq)\rightarrow K^+(aq)+OH^-(aq)

[KOH]=[OH^-]=[K^+]=0.100 M

Molariy of the KOH = 0.100 M

Volume of the KOH solution = 800 mL= 0.800 L

1 mL = 0.001 L

Moles of KOH = n

Molarity=\frac{Moles}{Volume(L)}

0.100 M=\frac{n}{0.800 L}

n = 0.0800 mol

Mass of 0.0800 moles of KOH :

0.0800 mol × 56 g/mol = 4.48 g

4.48 grams is the mass of potassium hydroxide that the chemist must weigh out in the second step.

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3 years ago
Both mechanical and electromagnetic waves _____.
Allushta [10]
The answer is C.
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3 0
3 years ago
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Compare an ionic and a molecular compound in terms of how each is formed
GREYUIT [131]

Answer:

Molecular compounds are pure substances formed when atoms are linked together by sharing of electrons while ionic compounds are formed due to the transfer of electrons.

Molecular compounds are made due to covalent bonding while ionic compounds are made due to ionic bonding.

Explanation:

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3 years ago
Which alkaline earth metal is a component of gypsum​
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Answer:

calcium is the correct answer :)

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3 years ago
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What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr
Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The  solution will be 0.27M hydrochloric acid  

3 0
3 years ago
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