Answer:
C. 10 W.
Explanation:
Hello!
In this case, since the power the person uses to lift the 10-N load is computed by using the formula:
![P=\frac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D)
Whereas W is the work and t the time; we can compute the work by multiplying the force applied in 1 m:
![W=10N*1m=10J](https://tex.z-dn.net/?f=W%3D10N%2A1m%3D10J)
Now, we divide it by the time to obtain:
![P=\frac{10J}{1s}=10W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B10J%7D%7B1s%7D%3D10W)
Since joules over seconds are watts.
Best regards!
Answer:
Decrease the volume to increase pressure and to increase concentration
Explanation:
A gaseous reaction is affected by the volume of the reactants. To increase the rate of the forward reaction, we need to ensure that the volume of the reactants is manipulated in such a way that the forward reaction is favored.
Thus, when the volume of reactants is decreased, the pressure increases.This increase in pressure has the same effect as increase in concentration. Hence, the rate of forward reaction increases.
The molar mass of the gas with the given mass and volume at the given temperature and pressure is 16.00g/mol.
<h3>What is the molar mass of the gas?</h3>
From the Ideal gas law or general gas equation;
PV = nRT
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )
Given that;
- Temperature T = 21°C = (21 + 273.15)K = 294.15K
- Pressure P = 745 mmHg = (745/760)atm = 0.98026atm
- Volume of the gas V = 3.97L
- Mass of gas m = 2.58g
First, we determine the amount of gas;
PV = nRT
n = PV / RT
n = ( 0.98026atm × 3.97L ) / ( 0.08206 Latm/molK × 294.15K )
n = 3.8916Latm / (24.137949Latm/mol)
n = 0.1612mol
Molar Mass = Mass of the gas / Amount of the gas
Molar Mass = m / n
Molar Mass = 2.58g / 0.1612mol
Molar Mass = 16.00g/mol
Therefore, the molar mass of the gas with the given mass and volume at the given temperature and pressure is 16.00g/mol.
Learn more about ideal gases here: brainly.com/question/15634266
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Answer: The name of this Hydrate is magnesium sulphate monohydrate.
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
a) If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of
= 87.0 g
Mass of
= 13.0 g
Step 1 : convert given masses into moles
Moles of
=![\frac{\text{ given mass }}{\text{ molar mass }}= \frac{67.0g}{120g/mole}=0.56moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%20%7D%7D%7B%5Ctext%7B%20molar%20mass%20%7D%7D%3D%20%5Cfrac%7B67.0g%7D%7B120g%2Fmole%7D%3D0.56moles)
Moles of
=![\frac{\text{ given mass}}{\text{ molar mass}}= \frac{13.0g}{18g/mole}=0.72moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%7D%7D%7B%5Ctext%7B%20molar%20mass%7D%7D%3D%20%5Cfrac%7B13.0g%7D%7B18g%2Fmole%7D%3D0.72moles)
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For
= ![\frac{0.56}{0.56}=1](https://tex.z-dn.net/?f=%5Cfrac%7B0.56%7D%7B0.56%7D%3D1)
For
=![\frac{0.72}{0.56}=1](https://tex.z-dn.net/?f=%5Cfrac%7B0.72%7D%7B0.56%7D%3D1)
Hence the empirical formula is ![MgSO_4.H_2O](https://tex.z-dn.net/?f=MgSO_4.H_2O)
Thus the name is magnesium sulphate monohydrate.