Taking into account the reaction stoichiometry, 3 moles of NH₃ will be formed.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
Li₃N + 3 H₂O → NH₃ + 3 LiOH
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Li₃N: 1 mole
- H₂O: 3 moles
- NH₃: 1 mole
- LiOH: 3 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Li₃N reacts with 3 moles of H₂O, 3.20 moles of Li₃N reacts with how many moles of H₂O?
<u><em>moles of H₂O= 9.6 moles</em></u>
But 9.6 moles of H₂O are not available, 9 moles are available. Since you have less moles than you need to react with 3.20 moles of Li₃N, H₂O will be the limiting reagent.
<h3>Mass of NH₃ formed</h3>Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 3 moles of H₂O form 1 mole of NH₃, 9 moles of H₂O form how many moles of NH₃?
<u><em>moles of NH₃= 3 moles</em></u>
Finally, 3 moles of NH₃ will be formed.
Learn more about the reaction stoichiometry:
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