I would say B.
Your starting term is 10, so that is your a1 value. Each time you add 4 to the number before, like 10+4=14 and so on, so that would mean (a-1)+4.
Answer:
It would be the first graph because |x| >5 is solved in two cases
The first case you keep everything the same, just get rid of the absolute value bars
x>5
The second case, you need to switch the sign and make the 5 negative
x<-5
When graphing you want to put an open circle on -5, and 5 because when it is < or > you have an open circle,
You then point the arrows going which ever way your sign is going, this is why the -5 is going to the left because the < sign is pointing left, and same with the 5, the arrow is going right because the > sign is pointing right
Hope this helps ;)
Answer:
2×sqrt(2) = 2.828427125...
Step-by-step explanation:
x = "a positive number"
x + 56/x = x³
x² + 56 = x⁴
x⁴ - x² - 56 = 0
(x² + 7)(x² - 8) = 0
this is true only for
x² = -7
or
x² = 8
x² = -7 would mean that x is an imaginary number. so, that is not a valid solution here.
x² = 8 means
x = sqrt(8) = sqrt(4×2) = 2×sqrt(2) = 2.828427125...
Answer:
[see below]
Step-by-step explanation:
I am assuming that you mean: 
.
The equation is in point slope form...
The point used in the equation is (2, 3). 2 replaces 'x1' and 3 replaces 'y1'.
If you convert the equation in to slope intercept form:
You get -5 as the y-intercept.
So, the line you draw would pass through points (2,3) and (0,-5).
Hope this helps.
