Explanation:
1.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils whereas erosion is the movement of weathered materials from one area to the other.
Erosion moves weathered materials and it causes them to change position. For example loose chips of rocks broken down as the rock weakens through alternate wetting and drying in tropical regions will remain in-situ until the agents of erosion comes to carry them away. The breaking is weathering and the carrying is erosion.
Learn more:
Wind erosion brainly.com/question/2115729
2.
Examples of mechanical weathering:
- Frost action
- Pressure release
Examples of chemical weathering:
There are two types of weathering:
- In mechanical weathering, a rock disintegrates into smaller chunks by the action of wind, water and glacier. For example in temperate and polar regions, water within rocks freezes. When water freezes it expands and causes tension within the rock. When temperature drops, water melts and the tension is relieved. This process causes a rock to crack. The crack will eventually become wider with time.
- In chemical weathering, a rock decomposes by the action of chemicals formed in the rock. In karst regions where limestone forms, combination of rain water and carbon dioxide forms weak carbonic acid that reacts with calcite in limestone.
Learn more:
Erosion brainly.com/question/2473244
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Started out as some other type of rock, but have been substantially changed from their original igneous, sedimentary, or earlier metamorphic form. Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors.
Do not ionize in solutions
Poor conductors of electricity/heat
Low melting/boiling points
gases or liquids at room temperature
Answer is: the absolute pressure of the air in the balloon is 1.015 atm (102.84 kPa).
n = 0.250 mol; amount of substance.
V = 6.23 L; volume of the balloon.
T = 35°C = 308.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.250 mol · 0.08206 L·atm/mol·K · 308.15 K / 6.23 L.
p = 1.015 atm; presure of the air.
