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iren2701 [21]
3 years ago
7

Uranium-234 decays to lead-214 through a series of alpha decays. Which of the following is the total number of alpha particles e

mitted in this decay series?
A. 1
B. 2
C. 5
D. 10
Chemistry
1 answer:
wariber [46]3 years ago
4 0
An alpha particle has a mass number of 4.
The mass number in the decay of uranium-234 to lead-214 decreases from 234 to 214, so by 20.
20 ÷ 4 = 5
5 alpha particles were emitted in this decay series. The answer is C.
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6 0
4 years ago
Given the equation: HCl + Na2SO4 → NaCl + H2SO4, if you start with 8 moles of hydrochloric acid, how many grams of sulfuric acid
Simora [160]

Answer:

392g sulfuric acid are produced

Explanation:

Based on the balanced equation:

2HCl + Na2SO4 → 2NaCl + H2SO4

<em>2 moles of HCl produce 1 mole of sulfuric acid</em>

<em />

To solve the problem we need to find the moles of sulfuric acid produced based on the chemical equation. Then, using its molar mass -<em>Molar mass H2SO4 = 98g/mol- </em>we can find the mass of sulfuric acid produced:

<em>Moles sulfuric acid:</em>

8mol HCl * (1mol H2SO4 / 2mol HCl) = 4 mol H2SO4

<em>Mass sulfuric acid:</em>

4mol H2SO4 * (98g / mol) =

392g sulfuric acid are produced

4 0
3 years ago
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77julia77 [94]

Answer:

3,29L

Explanation:

3.29L = V2

 

Formula: V1/T1 = V2/T2

--------------------

Given:

V1 = 3.0 L V2 = ?

T1 = 310 K T2 = 340 K

--------------------

Plugin:

(X stands in place of V2 just to make it easier to look at)

[3.0L / 310K = X / 340K]

(3.0L / 310K = 0.01L/K)

0.01L/K = X / 340K

(multiply 340K on both sides, it cancels out on the right)

0.01L/K * 340K = X

(0.01L/K * 340K = 3.29L)

**3.29L = X**

[or]

**3.29L = V2**

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B. When electrons gain energy, they have the power to move up to a higher energy level in an atom.

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3 0
3 years ago
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