I have found this variation on the ideal gas equation to be very handy.
PV = nRT ..... n = m / M.... where m is mass, M is molar mass
PV = mRT / M
m = PVM / RT
m = 1.75 atm x 3.00L x 28.0g/mol / 0.0821 Latm/molK / 295K
m = 6.07g
The grams of ammonia are in the flash is a total of 6.07 grams
Boiling-point elevation is a colligative property.
That means, the the boiling-point elevation depends on the molar content (fraction) of solute.
The dependency is ΔTb = Kb*m
Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.
A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:
(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg = 50/molar mass
=> 200 / 50 = 4.
Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.
Or, what is the same, the solution with higher molality will have the higher boiling point.
Answer:
2) MgO ---→ Mg + O2
Explanation:
Chemical decomposition is defined as the breakdown or breaking of a single molecule or entity into two or more smaller fragments.
Chemical decomposition is usually regarded as the exact opposite of chemical synthesis. In most cases, the chemical reaction in which two or more products are formed from a single reactant is called a decomposition reaction.
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