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Natali [406]
3 years ago
12

A scientist experiments ima unknown solution. She notices that when a base, sodium hydroxide, is added to the solution, it forms

a salt water. What can she infer from this observation?
(A) the unknown solution has a pH of 2.
(B) the unknown solution is acidic.
(C) the unknown solution contains oxygen.
(D) the unknown solution contains hydroxide ions.
Chemistry
2 answers:
Lelechka [254]3 years ago
8 0
The unknown solution is acidic
irga5000 [103]3 years ago
6 0

Answer:

(B) the unknown solution is acidic.

Explanation:

Hello,

In this case, as the unknown solution reacts with sodium hydroxide forming a salt water, one infers that the unknown solution is acidic since all the acids which react with bases form salts and water based on the shown below widespread chemical reaction:

Acid+Base-->Salt+Water

Which is a neutralization chemical reaction. It is clear that acidic solutions have pH lower than 7 but it is not enough to substantiate the unknown solution formed the salt after the addition of the base. However, the acid could have oxygen but it is not enough to justify the formation of a salt. Finally, it is impossible for the unknown solution to have hydroxide ions since a neutralization was carried out.

Best regards.

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What is the pH of a solution made by mixing 200 mL of 0.025M HCl and 150 mL of 0.050 M HCl?
seraphim [82]

Answer:

The answer to your question is pH = 1.45  

Explanation:

Data

pH = ?

Volume 1 = 200 ml

[HCl] 1 = 0.025 M

Volume 2 = 150 ml

[HCl] 2 = 0.050 M

Process

1.- Calculate the number of moles of each solution

Solution 1

                Molarity = moles / volume

-Solve for moles

                moles = 0.025 x 0.2

result

               moles = 0.005

Solution 2

               moles = 0.050 x 0.15

-result

                moles = 0.0075

2.- Sum up the number of moles

Total moles = 0.005 + 0.0075

                   = 0.0125

3.- Sum up the volume

total volume = 200 + 150

                     350 ml or 0.35 l

4.- Calculate the final concentration

Molarity = 0.0125 / 0.35

              = 0.0357

5.- Calculate the pH

pH = -log [H⁺]

-Substitution

pH = -log[0.0357]

-Result

pH = 1.45    

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3 0
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