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Natali [406]
3 years ago
12

A scientist experiments ima unknown solution. She notices that when a base, sodium hydroxide, is added to the solution, it forms

a salt water. What can she infer from this observation?
(A) the unknown solution has a pH of 2.
(B) the unknown solution is acidic.
(C) the unknown solution contains oxygen.
(D) the unknown solution contains hydroxide ions.
Chemistry
2 answers:
Lelechka [254]3 years ago
8 0
The unknown solution is acidic
irga5000 [103]3 years ago
6 0

Answer:

(B) the unknown solution is acidic.

Explanation:

Hello,

In this case, as the unknown solution reacts with sodium hydroxide forming a salt water, one infers that the unknown solution is acidic since all the acids which react with bases form salts and water based on the shown below widespread chemical reaction:

Acid+Base-->Salt+Water

Which is a neutralization chemical reaction. It is clear that acidic solutions have pH lower than 7 but it is not enough to substantiate the unknown solution formed the salt after the addition of the base. However, the acid could have oxygen but it is not enough to justify the formation of a salt. Finally, it is impossible for the unknown solution to have hydroxide ions since a neutralization was carried out.

Best regards.

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Dafna1 [17]
The coefficients in a chemical equation represent the molar ratio of the substances.

For example, if an equation says 2H2 + O2 ⇒ 2H2O, it means
2 moles of H2 + 1 mol of O2 ⇒ 2 moles of H2O.
8 0
3 years ago
Calculate the percent by mass of 4.35g of Na I dissolved in 105g of water​
Ludmilka [50]

<u>We are given:</u>

Mass of Na added = 4.35 grams

Mass of water = 105 grams

<u>Mass Percent of Na:</u>

Total mass of the solution = mass of solute + mass of solvent

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Mass percent of solute = (mass of solute / mass of solution) * 100

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4 0
2 years ago
4. Solve the following heat flow problem, being sure to show all your work (you may either type your
Viktor [21]

Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

  • Mass of graphite (m): 402 g
  • Heat absorbed (Q): 1136 J
  • Initial temperature: 26°C
  • Final temperature: 30 °C
  • Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

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5 0
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LuckyWell [14K]

Answer:

105

Explanation:

Density = mass/volume

therefore volume = mass/density

826/7.9=105 (To three significant figure)

8 0
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