A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘C. How many grams of this gasoline would fill a 15.7 gal tank
1 answer:
Th above problem asked us to find the amount of gasoline in grams given a density of 0.737 g/mL at 25°C and a volume of 15.7 gal.
To solve this problem, we must use the formula of density which is mass over volume.
D=
Base on the formula, we can find the mass of gasoline in by multiplying both sides by the volume. That is,
mass=D(Volume)
Note that we must cancel out the unit with a remaining g as the unit of mass. We must convert galloons to liters to mL.. That is
1 gal=3.78L and 1L=1000mL
15.7 gal x
x
=59346 mL
So,
mass=(0.737 g/mL x 59346 mL)=43738 g
To solve this problem, we must use the formula of density which is mass over volume.
D=
Base on the formula, we can find the mass of gasoline in by multiplying both sides by the volume. That is,
mass=D(Volume)
Note that we must cancel out the unit with a remaining g as the unit of mass. We must convert galloons to liters to mL.. That is
1 gal=3.78L and 1L=1000mL
15.7 gal x
So,
mass=(0.737 g/mL x 59346 mL)=43738 g
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Answer:- 14.0 moles of hydrogen present in 2.00 moles of .
Solution:- We have been given with 2.00 moles of and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .